How,Compute,Subnet,Mask,addres computer How to Compute an IP Subnet Mask
Gone are those times when the companies and the organisations didn't need a hi-tech system to handle them. Owing to the considerable increase in the business sector and thus, an enormous increase in the complexity of the organisational struc ----------------------------------------------------------Permission is granted for the below article to forward,reprint, distribute, use for ezine, newsletter, website,offer as free bonus or part of a product for sale as longas no changes a
IP address is a code that has host and network parts. Thehost bits describe a particular PC. The network prefix shows a network; itsmeasurement lengthwise depends on the class of network. Sub-netting helps toarrange a network by splitting it to several subnets. To describe such subnets,you should take bits from the portion of host of the IP address. That alsoexpands the network prefix. The subnet mask openly describes network and hostbits as 1/0, respectively. In this instance, we will compute a subnet mask for a PCwith IP address 193.35.127.93 that goes to network with 6 subnets. 1. Step 1 Verify the network class A/B/C based on IP addresses: * If the IP addresses start with 1 - 126, it is Class A.* If the IP addresses start with 128 - 191, it is Class B.* If the IP addresses start with 192 - 223, it is Class C. In our illustration, the network is class C because the IPaddress 193.35.127.93 begin with 192. 2. Step 2 Know the number of bits required to define subnets: * Number of subnets = (2^ # of bits) - 2. Therefore,* Number of bits = Log2(# of subnets + 2). In our illustration, there are 6 subnets: * Number of bits = Log2(6 + 2) = Log2(8) = 3. 3 bits in theIP address are utilized as a subnet portion. 3. Step 3 Create the subnet mask in a binary form by expanding theoriginal subnet mask w/ subnet bits. Original subnet mask for class A - C are: * 11111111.00000000.00000000.00000000 (Class A, network part= 8 bits)* 11111111.11111111.00000000.00000000 (Class B, network part= 16 bits)* 11111111.11111111.11111111.00000000 (Class C, network part= 24 bits) In our illustration, an addition of the default class Csubnet mask with three bits (Step 2) outcomes in the subnet mask11111111.11111111.11111111.11100000. 4. Step 4 Change the subnet mask binary to the decimal form. Thebinary form has 4 octets. Utilize the following rules: * Write 255 for "1111111" octet.* Write 0 for "00000000" octet. * If octet has 1 and 0 utilize the formula: Integer # is equals to (128 x n) + (64 x n) + (32 x n) + (16x n) + (8 x n) + (4 x n) + (2 x n) + (1 x n) Where N is 1 or 0 in the corresponding place in thesequence of octet. In our illustration, for 11111111.11111111.11111111.1110000011111111 = 25511111111 = 25511111111 = 25511100000 = (128 x 1) + (64 x 1) + (32 x 1) + (16 x 0) + (8 x0) + (4 x 0) + (2 x 0) + (1 x 0) = 224 The Subnet mask is 255.255.255.224.
How,Compute,Subnet,Mask,addres